11th BCS Preliminary Math Solution | BCS Exam Preparation

"This blog about BCS and Bank Job recruitment Test Question and Complete Solution"

BCS Math Solution | BCS Exam Preparation | Ratio

"This blog about BCS and Bank Job recruitment Test Question and Complete Solution"

BCS Shortcut Math Solution | Ratio

BCS Math Solution |Shortcut Method | BCS Exam Preparation | Interest rate, Principal, Time

"This blog about BCS and Bank Job recruitment Test Question and Complete Solution"

BCS Math Solution | Interest Rate, Principal, Time )

"BCS Math Solution | Shortcut Method | Tank related Maths

"This blog about BCS and Bank Job recruitment Test Question and Complete Solution

"BCS Math Solution | Shortcut Method | Tank related Maths

BCS Math Solution Shortcut Method (Work, Time, Labor)

"This blog about BCS and Bank Job recruitment Test Question and Complete Solution"

BCS Math Solution Shortcut Method (Work, Time, Labor)

Janata Bank Limited Assistant Executive Officer (Teller) 2015 Question With Complete Solution

Janata Bank Limited

Assistant Executive Officer (Teller) 2015

Mathematics

1. What will be the compound interest on a sum of TK. 25,000 after 3 years at the rate of 12 p.c.p.a.?

Solution: Amount=[25000×(1+12/100)³  ]

=(25000×28/25×28/25×28/25)

=35123.20

So, C.I.=( 35123.20-25000)

=10123.20

2. In a school, 10% of the boys are some in number as ¼ th of the girls. What is the ratio of boys to girls in the school?

Solution: 10% of boy=10/100 of boy =1/4 th of girl

So, boy/girl=100/(10*4)=5/2

3. If a number is decreased by 4 and divided by 6, the result is 8. What would be the result if 2 is subtracted from the number and then it is divided by 5?

Solution: Let, the number be x

x-4/6=8

or,x=6*8+4=48+4=52

Now, (52-2)/5=50/5=10

4. A 70 cm long wire is to be cut into two pieces such that one piece will be 2/5 as long as the other. How many centimeters will the shorter piece be?

Solution: Let the other piece be of length x cm, so the shorter piece = 2/5 of x =2x/5

Now, 2/5 x + x =70

Or, 7/5 x=70

Or, x=50 and 2/5 x=2/5 * 50 =20 cm

5. The Product of two numbers is 4107. If the H.C.F. of the these numbers is 37, then the greater number is :

Solution: Let the numbers be 37a and 37b

Then, 37a × 37 b = 4107

Or, ab = 3

Now, Co-primes with product 3 are (1,3)

So, the required numbers are (37 * 1, 37 *3) = (37, 111)

So, Greater number = 111

6. What will be the ratio of sample interest earned by certain amount at the same rate of interest for  6 years and that for 9 years?

Solution: Let the principal be P and rate of interest be R%

So, Required ratio = (P×R×6/100)/(P×R×9/100)

=6 PR / 9 PR

=2/3

=2:3

7. The average of six number is x and the average of three of these is y. If the average of the remaining three is z, then:

Solution: Average of 6 numbers = x

Sum of 6 numbers = 6 x

Average of the 3 numbers = y

Sum of the 3 numbers = 3y

Average of the remaining 3 numbers = z

Sum of the remaining 3 “  =3z

Now we know that 6x= 3y + 3z

Or, 2x = y + z

8. In what ratio must a grocer mix two varieties of pulses costing TK. 15 and TK. 20 per kg respectively so as to get a mixture worth TK. 16.50 per Kg?

Solution: By the rules of allegation:

Cost of Cheaper                  15 TK                                                            Cost of dearer 20 TK

                                                                                Mean Price

                                                                                   16.50 TK

              (20-16.50) or, 3.50                                                                              (16.50-15) or,1.50

9. When a commodity is sold for TK. 34.80, there is a loss of 2%. What is the cost price fo the commodity?

Solution: Sell price = 34.80; loss = 2%

Cost price = (100 × 34.80)/98 = 35.51

[Note: Correct answer not available in the question]

10. How long will a boy take to run round a square field of side 35 meters, if he runs at the rate of 9 km/hr?

Solution: Total length to cover = 4 sides of the square  = 4 × 35 meters

9 km/hr = 9000/(60×60 sec)

Time taken = (4 × 35 × 60 × 60)/9000 sec

=56 sec

11. The smallest 5-digit number exactly divisible by 41 is:

Solution: The smallest 5-digit number = 10000

If we divide 10000 by 41, 37 will be remainder

So, required number = 10000+ (41-37)= 10004

12. A, B, C hired a car for TK. 520 and used it for 7, 8 and 11 hours respectively. Hire charges paid by B were:

Solution: Hire charges paid by B = 520 × (8/7+8+11) = 160 TK.

13. The square root of 64009 is :

Solution: Square root of 64009 is 253

14. Which of the following is not a leap year?

Solution: The century divisible by 400 is a leap year

So, 700 is not a leap year

15. The ratio of the father’s age to his son’s age is 7:3. The product of their ages is 756. The ratio of their ages after 6 years will be:

 Solution: Let their age be 7x and 3x

Now, 7x × 3x =756

Or, x² = 756/(7×3)= 36

Or, x = 6

      After 6 year the ratio would be  = (7x+6)/(3x+6)

      = (7*6+6)/(3*6+6)

      = 2/1

      = 2 : 1

16. Two Pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full?

Solution: (A+B)’s 2 hour’s work when open A = 1/6 + 1/4   = 5/12

                “              1              “              “              “              = 5/12  * 2 = 5/6

Remaining work = 1-5/6 = 1/6

Now, it’s A’s turn in 5^th hour

1/6 work will be done by A in 1 hour

Total time = 4 + 1 = 5 hours

17. In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with the remaining meal?

Solution: There is a meal for 200 children, 150 children have taken the meal.

Remaining meal is to be catered to 50 children

Now, 200 children = 120 men

            50       “              =(120/200 * 50) = 30 men

18. (1000)⁷ ÷ 10¹⁸

Solution: (1000)⁷ / 10¹⁸ = {(10)³}⁷ / 10¹⁸ = 10²¹  / 10¹⁸ = 10^21-18 = 10³ = 1000

19. In a 200 meters race A beats B by 35 m or 7 seconds. A’s time over the course is:

Solution: B runs 35 m in 7 sec

B covers 200 m in (7/35 * 200) = 40 sec

B’s time over the course = 40 sec

A’s time over the course = (40-7) = 33 sec

20. 617 + 6.017 + 0.617 + 6.0017 = ?

Solution:  617 + 6.017 + 0.617 + 6.0017 = 629.6357

21. The 15% of 40 is greater than 25% of a number by 2, then the number is :

Solution: 15% of 40 = 25% of number + 2

Or, (15*40)/100 -2 = 25/100 * number

Or, 6-2 = 25/100 * number =

Or, Number = (4*100)/25 = 16

22. A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work they can finish in a day?

Solution: Given that B alone can complete the same work in day  = half the time taken by A = 9 days

A’s one day’s work = 1/18

B’s “       “              “     = 1/9

(A + B)’s one day’s work = 1/18 + 1/9 = 1/6

23. At 3.40, the hour hand and the minute hand of a clock form an angle of :

Solution: we use the formula= |11m – 60h|⁰ = |11*40 – 60*3|⁰ = 130⁰

24. The length of a rectangular hall in 5 m more than it’s breadth. The area of the hall is 750 m² . The length of the hall is :

Solution: Let, the breadth be b meter

b(b  +  5) = 750

or, b² + 5b – 750 = 0

or, b = 25, -30

so, breadth = 25 meter and length = 25 + 5 = 30 meter

25. What comes next in the series given?

                                    

?

Solution:

In Every Picture, one side is added. So after triangle, rectangle, pentagon there will be hexagon